Puzzle #17: The Puzzling Ways of Animals
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Solution to be posted next week or submit your own.
Crowder Mountain Bigfoot vs. World War II
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Today's question comes from BJ, in Rhode Island, who writes:
*Why the heck does The History Channel insist on showing those stupid
"MonsterQuest" episodes?...
3 years ago
3 comments:
4 raccoons + 6 mice = 12 squirrels + 14 mice
[Subtract 6 mice from each side of equation.]
4 raccoons = 12 squirrels + 8 mice
[Divide each side of equation by 4.]
1 raccoon = 3 squirrels + 2 mice
Assuming that all ropes intersected the poles at the halfway mark, and that all weight of tackle was negated out by its counter-tackle... then yes I agree, although in my head I worded it "5 mice & 1 squirrel"... but then again I suppose it's "Four of one, half a dozen of the other"
You know, I typically hate (the real version of) that cliche, but you had me laughing for a good ten minutes or so there, Bill.
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